Question

Work out (7x10^5)divide(2x10^2) give your answer in standard form

Answer 1

We need to recall the following definition of a standard form.

A standard form of a number is a way of writing the number as a multiple of exponent of $10$.

Given:

$\frac{7*10^5}{2*10^2}$

Use the property:  $\frac{a^m}{a^n} =a^{(m-n)}$

$\frac{7*10^5}{2*10^2}=\frac{7*10^{5-2}}{2}$

$\frac{7*10^5}{2*10^2}=\frac{7*10^{3}}{2}$

$\frac{7*10^5}{2*10^2}=3.5*10^3$

Use the property:  ${a^m}*{a^n} =a^{(m+n)}$

$\frac{7*10^5}{2*10^2}=35*10^3*10^{-1}$

$\frac{7*10^5}{2*10^2}=35*10^2$

Thus, the standard form of the number $\frac{7*10^5}{2*10^2}$ is $35*10^{2}$.

Answer 2

The value of the division of  $\frac{7\times 10^{5} }{2\times 10^{2} }$   is $3.5\times 10^{3}$.

Step-by-step explanation:

Given:

$\frac{7\times 10^{5} }{2\times 10^{2} }$    

To Find:

The value of the division of   $\frac{7\times 10^{5} }{2\times 10^{2} }$.

Solution

As given-  $\frac{7\times 10^{5} }{2\times 10^{2} }$.

$\frac{7\times 10^{5} }{2\times 10^{2} } = 3.5\times 10^{5-2}$

         $= 3.5\times 10^{3}$

 Thus, the value of the division of  $\frac{7\times 10^{5} }{2\times 10^{2} }$   is $3.5\times 10^{3}$.