Question

Work out the area of a rectangle with base, b = 16mm and perimeter, P = 52mm.

Answer 1

Answer:

given ,

         base(y)=16 mm, length=x(let) , perimeter=52 mm

Step-by-step explanation:

hence,

        P=2(x+y)

        52=2(x+16)

       26-16=x

       x=10 mm

therefore,

         area = x*y

          A=10*16=160 mm^2

I hope it helps.

Answer 2

The area of the rectangle = 160 $mm^{2}$

Step-by-step explanation:

Given,

The base of a rectangle (b) = 16 mm and

The perimeter of a rectangle (P) = 52 mm

To find, the area of a rectangle = ?

Let the length of a rectangle = l

We know that,

The perimeter of a rectangle (P) = 2(l + b)

⇒ 2(l + 16 mm) = 52 mm

⇒ l + 16 mm = 26 mm

⇒ l = 26 mm - 16 mm = 10 mm

∴ The length of a rectangle = 10 mm

The area of a rectangle = l × b

=  10 mm × 16 mm

= 160$mm^{2}$

Thus, the area of the rectangle = 160 $mm^{2}$