Question

Work out the area of a rectangle with base,
b
= 22mm and perimeter,
P
= 64mm.

Answer 1

Answer:

Perimeter = 2(l+b) = 64

l+b = 32

l = 32-b = 32-22 = 10

then

lenght = 10 mm

then area = L*b = 10×22 = 220 mm².

hope it helps.....

Answer 2

.$</p><p>\huge{\blue{\underline{\red{\mathbf{ ANSWER}}}}}$

${\bf{\green{area of rectangle}}}$

${\bf{\green{A=pl/2-l^2}}}$

${\bf{\green{A=(64)l/2-l^2}}}$

${\bf{\green{A=32l-l^2}}}$

${\bf{\green{area of rectangle=lb}}}$

${\bf{\green{A=l(22)}}}$

${\bf{\green{32l-l^2=22l}}}$

${\bf{\green{32l-22l=l^2}}}$

${\bf{\green{l^2=10l}}}$

${\bf{\green{l^2-10l=0}}}$

${\bf{\green{l(l-10)=0}}}$

${\bf{\green{l=0 or l=10}}}$

${\bf{\green{A=32(10)-100}}}$

${\bf{\green{A=320-100}}}$

${\bf{\green{A=220mm^2}}}$

${\bf{\green{A=22cm^2}}}$

${\bf{\green{A=0.22^2}}}$