Question

Work out the area of a rectangle with base, b = 26mm and perimeter, P = 72mm.

Answer 1

Hey mate !!!!!!

Here is ur answer......

Perimeter of rectangle=2(l+b)

72=2(l+26)

72=2l+52

2l= 20

=> L = 10 mm

Then area of rectangle = l*b

=10*26

=260mm²

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Answer 2

The area of the rectangle is 260 mm².

Step-by-step explanation:

Given : A rectangle with base, b = 26 mm and perimeter, P = 72 mm.

To find : The area of a rectangle ?

Solution :

The perimeter of the rectangle is $P=2(l+b)$

The base b=26 mm and perimeter P=72 mm

Substitute in the formula,

$72=2(l+26)$

$72=2l+52$

$2l=72-52$

$2l=20$

$l=\frac{20}{2}$

$l=10$

The length of the rectangle is 10 mm.

The area of the rectangle is $A=l\times b$

$A=10\times 26$

$A=260\ mm^2$

Therefore, the area of the rectangle is 260 mm².

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