Question

Work out the equation of the line which has a gradient of K and passes through the point (4, -2).​

Answer 1

Answer:

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Answer 2

Answer:

If you set up the equation to have a single y on the left-hand side, you end up with

y = ax + b (the b may occasionally be 0 in which case it can be omitted). When setting up an equation this way, the gradient and the value for a (the number of x’s) is the same.

So you start with y = (1/2)x. However, y clearly isn’t (1/2)x in the co-ordinate (4, -2). (1/2)x would be positive 2, and -2 is 4 less than that.

So your equation for the line with gradient of 1/2 which passes through (4, -2) is

y = (1/2)x - 4.

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