Question

Work out the following divisions.
() (10r - 25) = 5
(1) (10x - 25) = (2x - 5)
(ii) 10y(6y + 21) = 5(2y + 7)
(iv) 9x?y?(3z - 24) = 27xy(z-8)
(v) 96abc(3a - 12) (5b - 30) = 144(a - 4)(b-6)​

Answer 1

Answer:

(i) 5(2r-5) /5 = 2r-5

(ii) 5(2x-5) / (2x-5)

= 5

(iii) 10y × 3 ( 2y + 7) / 5(2y+7)

= 6y

(iv) 9x²y²× 3 ( z-8) / 9×3 ×xy (z-8)

=xy

(v) 96abc × 3(a-4) × 5( b-6) / 144 (a-4) (b-6)

= 10