Chemistry, asked by HarryD15, 15 hours ago

Work out the mass of iron sulphide produced when 5.6g of iron completely reacts with excèss sulphur.

Answers

Answered by whysarojkumar77

1

Answer:

$mol \: of \: fe = 5.6 \div 56 = 0.1mol \\ \\ fe \div fes = 1 \div 1 \\ \\ = 0.1 \div 0.1 \\ \\ mass \: of \: fes \: = 0.1 \times (56 + 32) = 8.8g$

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