Work out the surface area of this solid quarter-cylinder.
Give your answer in terms of π.
Answers
Answer:
12365
Step-by-step explanation: 12+4688 -47893
Given :-
Radius of solid quarter-cylinder = 10 cm.
Height of solid quarter-cylinder = 16 cm.
Formula used :-
Total surface area of solid quarter-cylinder = (TSA of cylinder / 4) + 2(Area of rectangle)= 2πr(h + r)/4 + 2(r * h) = πr(h + r)/2 + 2rh .
Solution :-
r = 10 cm.
h = 16 cm.
So,
→ Area of rectangle so formed = r * h = 10 * 16 = 160 cm².
then,
→ Area of two rectangles so formed = 2 * 160 = 320 cm².
Therefore,
→ Total surface area of solid quarter-cylinder = πr(h + r)/2 + Area of two rectangles.
→ Total surface area of solid quarter-cylinder = π * 10 * (10 + 16) / 2 + 320
→ Total surface area of solid quarter-cylinder = 5π * 26 + 320
→ Total surface area of solid quarter-cylinder = 5(26π + 64)
→ Total surface area of solid quarter-cylinder = 5*2(13π + 32)
→ Total surface area of solid quarter-cylinder = 10(13π + 32) cm². (Ans.)
Hence, Total surface area of solid quarter-cylinder is 10(13π + 32) cm².