Worker a takes 8 hours to do a job. worker b takes 10 hours to do the same job.how long should it take both a and b, working together but independently, to do the same job?(
Answers
Answer:
Step-by-step explanation:
A does in 8 hours. Hence, he does 1/8 part of job in 1 hour.
Similarly, B does 1/10 of job in 1 hour.
When they will work together on same job, they will do [(1/8)+(1/10)] of the job in one hour.
1/8+1/10⇒ (5+4)/40
⇒ 9/40
They do 9/40 of job in 1 hour.
So, they do the job in 40/9 days. {40/9 days= 4.4 days or 4 days and 6 hours)
Hope it helps you....
Given,
Time taken by worker A = 8 hours
Time taken by worker B = 10 hours
To find,
Time taken by both to do the same job.
Solution,
We can easily solve this numerical problem by following the given steps.
Now,
Time taken by worker A = 8 hours
Work done in 1 hour by A = 1/8
Time taken by worker B = 10 hours
Work done in 1 hour by B = 1/10
When they will be doing work together,
Work done both by A and B together in one hour(W) = 1/8 + 1/10
W = 1/8 + 1/10
W = 5+4/40 ( Adding the two rational numbers by finding the L.C.M. of 8 and 10)
W = 9/40
Time taken to complete the work by both A and B (T) = 40/9
T = 4.4 hours
( Time was given in hours. So, here the unit of time will also be an hour.)
Hence, it will take 4.4 hours for both A and B to do the same job together but independently.