Math, asked by sharmaminoti86, 8 months ago

working individually A,B and C can finish a piece of work in 16 days ,20 days respectively. In how many days can A,B and C together complete a work which is 3 1/2 times the previous work​

Answers

Answered by Anonymous
19

Answer:

24 days

Step-by-step explanation:

In 1 day A can do 1/16th

in 1 day B can do 1/20th

in 1 day C can do 1/30th

in 1 day (A+B+C) can do(1/16+1/20+1/30)th

=7/48th

total work they can complete in 1÷7/48 = 48/7 days

7/2 times of previous work they can do in

(48×7)/(7×2) = 24days

Answered by diya6152
2

Answer:

24 days

Step-by-step explanation:

In 1- day A,B and C can do= 1/16+1/20+1/30 =(15+12+8)/240 =35/240 part of the work. Thecomplete work can be done in = 240/35 days. = 24 days.

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