Math, asked by vishnupatil67, 1 year ago

Working individually A,B,C can finish a piece of work in 16 days,20 days and 30 days respectively.in how many days can A,B,C together complete a work which is 7÷2 times previous work

Answers

Answered by dibyendu2
27
in 1 day A can do 1/16th
in 1 day B can do 1/20th
in 1 day C can do 1/30th
in 1 day (A+B+C) can do(1/16+1/20+1/30)th
=7/48th
total work they can complete in 1÷7/48=48/7 days
7/2 times of previous work they can do in
(48×7)/(7×2)=24days

vishnupatil67: Thanks
Answered by SM907
1

Step-by-step explanation:

Working individually A,B,C can finish a piece of work in 16 days,20 days and 30 days respectively.in how many days can A,B,C together complete a work which is 7÷2 times previous work

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