Math, asked by jagannath1prasad, 8 months ago

Working individually, A takes 18 days,
B takes 20 days and C takes 30
days to complete a work. If B and C
were engaged for first 2 days, in how
many days the rest of the work shall
be completed by engaging A alone ?
(1) 12 (2) 13
(3). 14. (4) 15
(5) 16​

Answers

Answered by systemboss
2

Answer:

answer (4) 15

Step-by-step explanation:

A = 18 days

B = 20 days

C = 30 days

total work = LCM of 18, 20, 30

= 180

A's efficiency = 180/18 = 10

B's efficiency = 180/20 = 9

C's efficiency = 180/30 = 6

2 days for B+C = (9+6)*2

= 30

rest work = 180 - 30

= 150

A take time to complete the work = 150/10 = 15 days

Answered by sanjaybhai5777
0

15 days A will take to engage

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