Question

working the choke coils

Answer 1

Choke is very important of Tube light. Usually tube light doesn't work without choke.

Working: 

Normal operating voltage of tube light is about 110 but naturally available voltage is 240 V in India hence the choke comes into picture which gives 110 V output.

But for initiating the light (to ionize the gas in the tube) the system, system requires 800 - 1000 V to provide this starter has been used, which block the current flowing from the choke to light hence the voltage will build up across the load. once the maximum voltage reached which starter can withstand, the starter closes the circuit and the build up voltage applied across tube light.

Principle:-
Choke is actually an Inductor As we know inductor opposes the rate of change of current here we are making current I which is intially drawn to zero with the help of bimetallic contacts present in starter

According to formulae E=L*di/dt here L is constant and di is equal to I-0 and dt is time taken for I to become zero Accordingly high voltage is induced and this voltage is sufficient to drive the electrons from one electrode to another electrode inspite of medium present between electrodes.

Once conduction starts there after choke just provide voltage which is sufficient for conduction i.e. 110V.

Choke is shown in Tube light circuit as:-




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Answer 2

THE ABOVE ANSWER IS CORRECT ....BECAUSE ITS BY MY OLD ACCOUNT