Working together, A and B can complete a piece of work in 12 days, B and C can complete the same piece of work in
15 days. If A is as twice efficient as C, then the time taken by B alone to complete the same piece of work is:
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time taken by b is x
a+x=12
2a+x=15
2a+x=12+3
a=3
3+x=12
6+x=15
x=9
time taken by b is 9days
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