Math, asked by WhiteWolfBuchanan, 8 months ago

Working together it takes two different sized hoses 30 minutes to fill a small swimming pool. If it takes 50 minutes for the larger hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on its own? Do not do any rounding.

Answers

Answered by coolaman341
0

Answer:

The smaller hose fill the swimming pool in 75 minutes.

Step-by-step explanation:

Let the smaller hose be x

and, larger hose be y.

The hose (x + y) together fill the swimming pool in

30 minutes.

Then together in 1 minute (x+y) they fill 1/30 part of the swimming pool.

The hose y fill the swimming pool in 50 minutes.

Then in 1 minutes y fill 1/50 part of the swimming pool.

then in 1 minute the x hose fill the swimming pool

=(1/30) - (1/50)

=(2/150)

=(1/75)

then, hose x fill the swimming pool in 75 minutes.

if you get satisfied with the explanation . kindly follow and thanks me and also brainliest me. Because your appreciation is fuel, that encourage us to come next time with much more effort.

Similar questions