Math, asked by anju15gupta79, 2 months ago

Working together, printer A and printer B would finish a task in 24 minutes, Printer A alone would
finish the task in 60 minutes. How many pages does the task contain if printer B paints 5 pages a
minute more than printer A?
प्रिंटर Aऔर 8 प्रिंटर मिलकर किसी कार्य को 24 मिनट में खत्म करते हैं। प्रिंटर A अकेला किसी
काम को 60 मिनट में खत्म कर सकता है यदि प्रिंटर 8 एक मिनट में प्रिंटर से पेज खादा प्रिंट
करता है तो कुल कितने पेज प्रिंटर
a) 1200 b) 600
c) 300
d)400​

Answers

Answered by jayantisharma2006
2

total time taken by B = 24 * 60 / (60 -24) = 40 min. A take 60 min. B takes 40 min to complete a task

Answered by Anonymous
2

Answer:

total time taken by B = 24 * 60 / (60 -24) = 40 min.

A take 60 min. B takes 40 min to complete a task.

Now, divide the values given in option (in Ans) to get the rate per min.

option A: 600 / 10 = 60 & 600/40 = 15 > this satisfies the condition given in question stem that printer B prints 5 pages a minute more than printer A ?

. therefore A

Step-by-step explanation:

Ta = 60min

Ra = 1/Ta = 1/60

Rb = 1/Tb

Combined task completion time 24min.

=Ra + Rb

=1/60 + 1/Tb = 1/24

Tb = 40 min.

Ra = X/Ta Rb = X/Tb

Ra + 5 = Rb

X/Ta + 5 = X/Tb

X/60 + 5 = X/40

X=600 Ans.

thanks

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