Working7A stone of mass 10 g is thrown vertically upwards. Its minimum and maximumdistance from a fixed point A is 6 m and 65 m, respectively. When the stone is atthe maximum height, it is at a distance 10 m from point A. Find initial kineticenergy of the ball.a. 1 Jb. 2 JC. 3 Jd. 4 J
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Answer:
Let u be the initial velocity and h be the maximum height attained by the stone.
v
1
2
=u
2
−2gh,
(10)
2
=u
2
−2×10×
2
h
100=u
2
−10h ....(i)
Again at height h,
v
2
2
=u
2
−2gh
(0)
2
=u
2
−2×10×h
u
2
=20h ... (ii)
So, from Eqs. (i) and (ii) we have
100=10h
h=10m
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