Workman
Workman 2
a) Workman 1 drops a hammer, which falls to the ground.
The hammer has a mass of 2.0 kg, and is dropped from a
height of 4.8 m above the ground. (g = 10m/s?)
(i) Calculate the change in gravitational potential
energy of the hammer when it is dropped.
(ii) Describe the energy changes from the time the
hammer leaves the hand of workman 1 until it is
at rest on the ground.
b) Workman 2 picks up the hammer and takes it back, up the
ladder to workman 1. He climbs the first 3.0 m in 5.0 s. His
total weight, including the hammer, is 520 N.
Calculate the power which his legs are producing.
Answers
Given : Workman 1 drops a hammer, which falls to the ground. The hammer has a mass of 2.0 kg, and is dropped from a height of 4.8 m above the ground. (g = 10m/s?)
climbs the first 3.0 m in 5.0 s. His total weight, including the hammer, is 520 N.
To Find : Calculate the change in gravitational potential energy of the hammer when it is dropped.
(ii) Describe the energy changes from the time the hammer leaves the hand of workman 1 until it is at rest on the ground.
Calculate the power which his legs are producing.
Solution:
The hammer has a mass of m = 2.0 kg
Dropped from a height of h = 4.8 m above the ground.
g = 10 m/s²
PE = mgh = 2 * 10 x 4.8 = 96 Joule
KE = 0 as at rest
TE = 96 Joule
PE at ground = 0 as h = 0
Hence change in PE = 0 - 96 = - 96 Joule
PE converted into KE and then converted into Heat/Sound Energy.
Work done = 520 x 3 = 1560 joule
power = Work done/ Time
=> Power = 1560/5
=> Power = 312 J/s
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