Question

workout the surface area of the following shapes: ​

Answer 1

Answer:

pls consider the picture

Answer 2

Area of the figure is 3410 cm ²

Step-by-step explanation:

here , consider the first cubiod

dimensions are 23×18×3

then surface area of cuboid (1) = 2(lb +bh+hl)

= 2(23×18+ 18×3+23×3)

= 2(414+54+69)

= 2(537)

= 1074 cm²

consider the second  cuboid

dimensions are 20×8×18

then surface area of cuboid (2) = 2(lb +bh+hl)

= 2(20×8+8×18+18×20)

= 2(160+144+360)

=2(664)

= 1328 cm²

consider the third   cuboid

dimensions are 18×5×18

then surface area of cuboid (3) = 2(lb +bh+hl)

= 2(18×5+5×18+18×18)

=2(90+ 90+324)

=2(504)

= 1008 cm ²

then area of the figure = area of cuboid 1 + area of cuboid 2 + area of cuboid 3

=  1074 cm²+1328 cm²+1008 cm ²

= 3410 cm ²

hence , Area of the figure is 3410 cm ²

#Learn more:

Workout the surface area of the following shape ​18 cm,3cm,3cm ,8cm,2cm,5cm,18cm

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