Question

WORKSHEET - 1
Q1 to Q8 carry 1 mark each
For what value of k do the equations
3x-y+ 8 = 0 and 6x-ky + 16 = 0 represent
coincident lines?
29x +
solution
betwee
For w
linear
10x
15 students of class XII took part in
Mathematics quiz. If the number of girls is 5
more than the number of boys. Represent
this situation algebraically.
20*​

Answer 1

see the answer of ques 1 in picture

Answer 2

Given equations : 3x-y+ 8 = 0 and 6x-ky + 16 = 0

To find : The value of k

Solution :

equations :

3x-y+ 8 = 0

6x-ky + 16 = 0

here

$a_1 = 2 , b_1 = -1, c_1 = 8\\\\a_2 = 6 , b_2 = -k, c_2 = 16$

for equations to be coincident

it must follow the condition

$\frac{a_1}{a_2}= \frac{b_1}{b_2}= \frac{c_1}{c_2}\\\\\frac{3}{6}=\frac{1}{k}=\frac{8}{16}\\\\\frac{1}{2}= \frac{1}{k}=\frac{1}{2}$

so ,The value of k must be 2

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