Question

workshut
QUADRATIC EQUATIONS
5. Prove that each of the following
equation has only one solution
find the solution
a) 4ysquare -28y +49 = 0​

Answer 1

Answer:

a quadratic equation is a type of equation which has a degree of 2 like ax^2 + bx + c = 0 , the zero is necessary for this to be a equation .

Answer 2

Step-by-step explanation:

4y² - 28y + 49 = 0

a = 4, b = -28 and C = 49

D = b² - 4ac => (-28)² - 4×4×49

=> 784 - 784 => 0

As the discreminent is zero, the given equation has only one solution

if D > 0, two solutions

it D < 0, no real solutions

x = [-b ± √D] / 2a

x = [-(-28) ± 0] / 2×4

x = 28/8 => 3.5 Solution