Question

wothout avtual division show that p(x) =4x^3+3x^2-4x-3 is exactly divisible by (x+1) and (4x-3)​

Answer 1

Step-by-step explanation:

p(x)=4X^3+3x^2-4x-3

exactly devisible by x+1 then p(x)=0

p(-1)=4(1)^3+3(1)^2-4(1)-3

p(-1)=4+3-4-3=0

so it is exactly devisible by (x+1)

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Answer 2

Answer:

Step-by-step explanation: