Question

would really appreciate if u could help me today​

Answer 1

Answer:

You just need to prove ΔAFO and ΔAEO congruent. That way you can show ∠ BAO = ∠ CAO. Thus, OA is the angle bisector of angle A.

Step-by-step explanation:

As OB and OC are angle bisectors,

∠ABO = ∠OBC and ∠ACO = ∠OCB

ΔFOA ≅ ΔEOC by AAA

Therefore ∠FOA = ∠EOA and FO=EO              - (i)

Now, in ΔAFO and ΔAEO:

Using, AO = AO and equation (i)

ΔAFO ≅ ΔAEO by SAS

Thus, ∠FAO = ∠EAO

Therefore, OA is the internal angle bisector of ∠A.

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Answer 2

the answer is in the picture

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