Would you someone tell me that in which step there is a flaw or what's wrong in this...
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the step 3 Is wrong which made the steps after it wrong
adisree5183:
welcome
:-) ☺
Its actually step 4. coz till step 3 is fine. but you cannot divide by (a-b) when a=b. coz division with 0 is considered indeterminate state in mathematics. Hence, we use higher concepts like Limits and calculus to resolve division with 0's (example: tending to 0 but not exactly 0)
Yeah...You're right!
@WonderGirl Thanks :)
Aww...You are welcome :-) @jish4you
Answered by
1
in the third step the ques there is a flaw.
if the value of a=b , would hv been substituted
2 : b*b -b²=b²-b²
b²-b²= b²-b²
0=0
and even in situation 3, if we
3: b(b-b)= (a + b)(b - b)
b(0) =(a + b )(0)
0=0
if the value of a=b , would hv been substituted
2 : b*b -b²=b²-b²
b²-b²= b²-b²
0=0
and even in situation 3, if we
3: b(b-b)= (a + b)(b - b)
b(0) =(a + b )(0)
0=0
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