Question

Writ two Pythagoreas triplet whose one of the number is 5

Answer 1

Let 2m= 5

M=2.5

M square-1

=2.5 square-1

=1.5

M square +1

2.5+1

=3.5

Therefore the two other members are 1.5 &3.5

Answer 2

pythagorean triplet is
${m}^{2}-1$
2m
${m}^{2} + 1$
here
${m}^{2} + 1 = 5 \\ {m}^{2} = 5 - 1 \\ {m}^{2} = 4 \\ m = 2$
so triplet is 2m=4

${m}^{2} - 1 = 4 - 1 = 3 \\ {m}^{2} + 1 = 4 + 1 = 5$
4,3,5