Question

writa a quadratic polynomial , sum of whose zeroes is 2 and product is 18​

Answer 1

sum of zeros (a+b) = -7

product of zeros (ab) = -18

from the formula to find quadratic polynomial

x²- (a+b)x+ ab

x²- (-7+(-18))x +(-7)(-18)

x²-(-7-18)x + 126

x²-(-25)x + 126

x²+25x+126 is the quadratic polynomial of the given zeros -7&-18

and the zeros we get is -7 & -18 as given in the question but if you need to verify it

then

x²+ 25x +1 26=0

x²+ 18x + 7x +126=0

x(x+18) + 7(x+18)=0

(x+7)(x+18)=0

x+7=0 or x+18= 0

x= -7 or x= -18

hence in the question there were same zeros after verification

hope you help this solution ☺️☺️

PLZ MAKE IT BRAINLIEST

Answer 2

we know the that the quqdratic form is :-

k ( x- (sum of zeroes)x+ product of zeroes)

so, k( x- 2x+ 10)

let k be the constant and k=0

so , the required quadratic polynomial is x-2x+10