write 1.256 (bar on 56) in p\q form?
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Step-by-step explanation:
Let x=1.2565656.........eq-1
Here the periodicity is 2 so we should multiply
the eq 1 by 100 on both sides
100×x=1.2565656.......×100
100x=125.656565.....eq-2
Subtract equation 2 from 1
100x=125.656565...
- x= 1.256565...
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99x=124.40000000...
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99x=124.4
X=1244/10×1/99
X=622/495
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