write (1+2i) (1+3i) (2+i) in form of a+bi
Answers
Answered by
1
Answer:
{(1+2i)(1+3i)}(2+i)
(1+3i+2i-6)(2+i)
(-5+5i)(2+i)
-10-5i+10i-5
-15+5i
Answered by
10
Answer:
-5(3-i)
Step-by-step explanation:
=(1+2i)(1+3i)(2+i)
=[1(1+3i)+2i(1+3i)](2+i)
=(1+3i+2i+6i²)(2+i)
=(-5+5i)(2+i)
=-5(2+i)+5i(2+i)
=-10-5i+10i+5i²
=-15+5i
=-5(3-i)
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