write (1+2i)(3+1)(2+i)-1in the form of a+in
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=(1+2i) 4 (2+i) -1
=4(2+i+4i+ 2 i^2 ) -1
= 4(2 +5i + 2×-1)-1 [ i^2 =-1]
= 4( 5i)-1
= 20 i -1
= -1 + 20 i
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