Write −1 + 2i in the polar form.
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Step-by-step explanation:
Using these formulas, we can convert the complex number into polar form. Hence, the polar form of $ - 2i$ is $2(\cos \dfrac{{3\pi }}{2} + i\sin \dfrac{{3\pi }}{2})$ .
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Hence: arg(1−2i)=arctan(−2)=−arctan2
Step-by-step explanation:
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