Write 1+i3/2 into polar form step by step answer…!! Please
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Answer:
z=√1^2+(3/2)^2
=√13/4
=√13/2
1=rcosθ
1=√13/2cosθ
cosθ=1/√13/2
θ=cos^-1(2/√13)
similarly,
3/2=r sinθ
=√13/2sinθ
θ= sin^-1(√13/3)
so polar form is:
√13/2(cos^-1(2/√13)+sin^-1(√13/3))
Step-by-step explanation:
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