write 1041 as the difference of the squares of two consecutive natural numbers
Answers
Answered by
20
hey
let one number be x
so it consecutive will be x+1
according to question
diff. of squares of two consecutive no. is 1041
x²-(x+1)²=1041
x²-x²-1-2x=1041
-1-2x=1041
-2x=1042
x=-1042/2
=521
thanks
let one number be x
so it consecutive will be x+1
according to question
diff. of squares of two consecutive no. is 1041
x²-(x+1)²=1041
x²-x²-1-2x=1041
-1-2x=1041
-2x=1042
x=-1042/2
=521
thanks
simmykaurr:
thanks
Answered by
3
Answer:
the answer is equal to 521
Step-by-step explanation:
I I hope it works.
please rate me .
Attachments:
Similar questions
Physics,
7 months ago
English,
7 months ago
Social Sciences,
1 year ago
Science,
1 year ago
English,
1 year ago