Write 10th term from the end of the A.P. 3, 5, 7, 9, ...., 201.
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Answered by
9
In the given A.P.,
a = 3
d = 2
l = 201
We can find the last term of an A.P. by using the formula:
[tex] a_{n}= l-(n-1)d \\ a_{n} =201-(10-1)2 \\ a_{n}=201-18=183[/tex]
Hence, the 10th term from the end of the A.P. is 183.
a = 3
d = 2
l = 201
We can find the last term of an A.P. by using the formula:
[tex] a_{n}= l-(n-1)d \\ a_{n} =201-(10-1)2 \\ a_{n}=201-18=183[/tex]
Hence, the 10th term from the end of the A.P. is 183.
ali4249:
how can be the difference be 5
Answered by
0
Answer:
183.
Step-by-step explanation:
Given,
Arithmetic Progression = 3, 5, 7, 9,.... 201.
Now,
In the given Progression:
a = 3
d = 2
(where, d is the difference between two progressions.)
l = 201
We can find the last term of an A.P. by using the formula:
−(r−1)d
To Find,
10th term from that last of the progression will be:
= 201-(10-1)2
= 201-18
= 183
Hence, the 10th term from the end of the A.P. is 183.
#SPJ2
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