write 10th term of ap 5 9 13
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Answer:
given A.P = 5,9,13.
d= t2-t1
d= 9-5 = 4.
tn= a+(n-1)d
t10= 5+(10-1)4
t10= 5+9x4
t10= 5+36
t10= 41.
Therefore, 10th term of the given equation is 41.
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