Question

write 11 's square in the sum of odd numbers​

Answer 1

Answer: 1+3+5+7+9+11+13+15+17+19+21 = 121

No of successive addition = 11

11^2 = 121

Answer 2

121

Step-by-step explanation:

Such type of numbers that can only be divisible by one and itself is known as odd numbers like 1,3,5 and some others. And those numbers that can be divisible by 2 and no remainder is left is called as even numbers such as 2,4,6 and some others.

The sum of odd number = $n^2$

Where n = number of terms

$2+3+5+7+9+11+13+15+17+19+21\\(11)^2=121$