Question

Write 11x – 4 = √3 y in the form of ax+by+c =0 and write the values of a, b and c

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Answer 1

Answer: ( i ) 2x + 3y - 9.35 = 0

( ii ) 5x - y - 50 = 0

( iii ) - 2x + 3y - 6 = 0

( iv ) x - 3y + 0 = 0

( v ) 2x + 5y + 0 = 0

( vi ) 3x + 0y + 2 = 0

( vii ) 0x + y - 2 = 0

( viii ) - 2x + 0y + 5 = 0

Step-by-step-explanation:

We have given some linear equations in two variables.

We have to express them in the general form

ax + by + c = 0 and indicate the values of a, b and c.

( i ) 2x + 3y = 9.35

➞ 2x + 3y - 9.35 = 0

Comparing with ax + by + c = 0, we get,

a = 2

b = 3

c = - 9.35

( ii )

Multiplying each term by 5, we get,

➞ 5x - y - 50 = 0

Comparing with ax + by + c = 0, we get,

a = 5

b = - 1

c = - 50

( iii ) - 2x + 3y = 6

➞ - 2x + 3y - 6 = 0

Comparing with ax + by + c = 0, we get,

a = - 2

b = 3

c = - 6

( iv ) x = 3y

➞ x - 3y + 0 = 0

Comparing with ax + by + c = 0, we get,

a = 1

b = - 3

c = 0

( v ) 2x = - 5y

➞ 2x + 5y = 0

➞ 2x + 5y + 0 = 0

Comparing with ax + by + c = 0, we get,

a = 2

b = 5

c = 0

( vi ) 3x + 2 = 0

➞ 3x + 0y + 2 = 0

Comparing with ax + by + c = 0, we get,

a = 3

b = 0

c = 2

( vii ) y - 2 = 0

➞ 0x + y - 2 = 0

Comparing with ax + by + c = 0, we get,

a = 0

b = 1

c = - 2

( viii ) 5 = 2x

➞ 5 - 2x = 0

➞ - 2x + 5 = 0

➞ - 2x + 0y + 5 = 0

Comparing with ax + by + c = 0, we get,

a = - 2

b = 0

c = 5

Step-by-step explanation:

Answer 2

Thanks for your question...

Your required answer :

Given eq :

• 11x – 4 = √3 y

To write :

• In ax+by+c = 0 form

To find :

• Values of a , b and c

Solution :

In ax + by + c = 0 form :

• 11 x - √3y - 4 = 0

Now values :

• a = 11 x
• b = -√3y
• c = -4

Brainliest Please