write 131 as the difference of the squares of two consecutive numbers
Answers
Answered by
17
Let the consecutive no be x, x+1
So
131 difference of square of consecutive no
So
X²-(x+1)²=131
Its identity match from a² -b²=(a+b)(a-b)
(X+x+1)(x-x+1)=131
2x+1+1=131
X=129/2
So
131 difference of square of consecutive no
So
X²-(x+1)²=131
Its identity match from a² -b²=(a+b)(a-b)
(X+x+1)(x-x+1)=131
2x+1+1=131
X=129/2
Answered by
7
(x)^-(x+1)^=131
x^_(x^+1+2x)=131
x^-x^-1-2x=131
-2x=131+1
-2x=132
×=132/-2
×='66
so no are
66,67
x^_(x^+1+2x)=131
x^-x^-1-2x=131
-2x=131+1
-2x=132
×=132/-2
×='66
so no are
66,67
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