Question

write 131 as the difference of the squares of two consective numbers

Answer 1

the square of two consective no is 66

Answer 2

$let \: the \: consecutive \: numbers \: be \\ x \: \: and \: \: x + 1 \\ {(x + 1)}^{2} - {x}^{2} = 131 \\ 2x + 1 = 131 \\ x = 65$
Therefore numbers are 65 & 66