write (-2, -8) and (6, 4) in slope intercept form
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Answer:
slope =m=y2-y1/x2-x1
m=4-(-8)/6-(-2)
m=12/8
m=3/2
y intrecept = put x=0 in equation of this line then
equation of this line is
y-y1/y1-y2=x-x1/x1-x1
y-(-8)/-8-4=x-(-2)/-2-6
y+8/-12=x+2/-8
y+8/3=x+2/2
2y+16=3x+6
3x-2y-10=0
so y intrecept is -5
slope point form
y=MX+c
y=3/2x-5
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