Question

write 2 arithmetic sequences with 200 as the sum of four numbers​

Answer 1

Answer:

First number be n

Try with different A.P with different difference

1)With difference d=2

n+n+2+n+4+n+6=100

4n+12=100

n=88/4

n=22

Therefore first A.P 22,24,26,28….

2)With difference d=4

n+n+4+n+8+n+12=100

4n=100–24

4n=76

n=19

Second A.P 19,23,27,31…

3)With difference d=6

n+n+6+n+12+n+18=100

4n=100–36

4n=64

n=16

Third A.P 16,22,28,34…

4)With difference d=8

n+n+8+n+16+n+24=100

4n=100–48

4n=52

n=13

Fourth A.P 13,21,29,37

Step-by-step explanation:

hope you have been understood

Answer 2

Answer:

First number be n

Try with different A.P with different difference

1)With difference d=2

n+n+2+n+4+n+6=200

4n+12=200

n=88/4

n=22

Therefore first A.P 22,24,26,28