Write 2 log 3 + 3 log 5 - 5 log 2 as a single logarithm.
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as the formula. a log n=log n^a
Step-by-step explanation:
then
log3^2+log5^3-log2^5
log9+log125-log32
as the formula. logA-log B=loga/b
log 9+log125/32
log9+log 3.906
loga+logb=loga.b
log9X3.906
log35.184
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