write 2log3+2log5-5log2 as a single logarithm
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Answered by
0
Answer:
log7. 03
Step-by-step explanation:
2log3+2log5-5log2
log3*3+log5*5-log2*2*2*2*2
log9 + log25 - log32
log(9*25)/32
log225/32
log7. 03
Answered by
0
Answer:
for your question the answer is
( steps are below)
Step-by-step explanation:
. First use the power law
>>log 3^2 + log 125 ) log 32 ( using quotient law )
>> log ( 9 * 125 / 35 )
>> = log = 35 . 156
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