Question

Write 2log3-3log2 as single term

Answer 1

Step-by-step explanation:

$=>2log3-3log2 \\\\ =>log3^2-log2^3 \\\\ =>log(3\times3)-log(2\times2\times2) \\\\ =>log9-log8 \\\\ =>log(\frac{9}{8}) \\\\\\ \implies nloga=loga^n \\ \implies logm-logn=log(\frac{m}{n})$

Answer 2

Answer:

2+3log2 - 2log5= log 100 + log 8 - log 25

= log 800 - log 25

= log 32

Basically make 2 into log 100, and using power law make 3log2 into log 8 and 2log5 into log 25.

Then use bodmas and add log 100 and log 8 and you will get log 100 based on the rule.

Then subtract log25 from log 800 then you will get log 32

Thankyou,

By

Aaditya Singh