Write 2log3-3log2as single logarithm
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Hello Dear!!!
Here's your answer...
Given,
2log3 - 3log2
log3² - log2³
log 9 - log8
we know that,
log m - log n = log m/n
log9/8
_______________________________________
HOPE THIS HELPS YOU.....
Here's your answer...
Given,
2log3 - 3log2
log3² - log2³
log 9 - log8
we know that,
log m - log n = log m/n
log9/8
_______________________________________
HOPE THIS HELPS YOU.....
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