Math, asked by zafarmutayyib, 1 month ago

write 2log3+3log5–5log2 as a single logarithm

Answers

Answered by Anonymous

1

Answer:

log(1125/32)

Step-by-step explanation:

2log3+3log5-5log2=log3^2+log5^3-log2^5=

log9+log125-log 32=log(9×125)-log32=log1125/32

Answered by somisettyyogendra

2

Answer:

2log3+3log5-5log2

log3²+log5³-log2⁵

log9+log125-log32

log(9×125)-log32

log1125-log32

log1125÷log32.

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