write (2x-1)/3 - 2/(x+1) as a single fraction
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Answer:
(x-1)(2x + 3)/(x+1)
Step-by-step explanation:
2x-1/3 - 2/x+1
=(x+1)(2x-1)/3 (x+1) - 2 /(x+1)
= 2x^2+x-1 - 2 /(x+1)
= (2x^2 + x - 3 )/(x + 1)
Numerator = 2x^2 +x3 - 2x -3
= `(x-1)(2x + 3)
Denominator = x + 1
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