Write 2x +3 = 7y into standard form of linear equation and indicate the value of a, b and c
Answers
Answer:
(i) We have
-2x +3y = 12
-2x +3y -12 = 0
On comparing this equation with ax +by +c = 0 we obtain a = -2, b =3 and c = -12.
(ii) Given that
x - y/2 -5 = 0
1x - y/2 -5 = 0
On comparing this equation with ax +by +c = 0 we obtain a =1, b = 1/2 and c = -5
(iii) Given that
2x + 3y = 9.35 bar
2x +3y - 9.35 bar = 0
On comparing this equation with ax +by +c = 0 we get a = 2, b =3 and c = -9.35 bar
(iv) 3x = -7y
3x +7y +0 = 0
On comparing this equation with ax +by +c = 0 we get a =3, b =7 and c = 0
(v) We have
2x +3 = 0
2x + 0(y) +3 =0
On comparing this equation with ax + by + c = 0 we get a =2, b=0, and c =3
(vi) Given that
y -5 = 0
0x + 1y -5 = 0
On comparing this equation with ax + by +c = 0 we get a =0, b =1 and c = -5
(vii) We have
4 = x
-3x + 0.y +4 = 0
On comparing the equation with ax + by +c = 0 we get a = -3, b = 0 and c =4
(viii) Given that,
y = x/2
2y = x
x -2y +0 =0
On comparing this equation with ax +by +c = 0 we get a =1, b =-2 and c= 0
Step-by-step explanation:
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Answer:
Answer
(i) 2x+3y=9.3
5
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⇒2x+3y−9.3 5ˉ
Comparing the equation with ax+by+c=0
a=2,b=3,c=−9.3
5
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