write (2x +5)2 = x-2 in form ax2 +bx +c =0
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Answer:
Step-by-step explanation:
Open the square formula for (2x+5)^2
4x^2+25+20
so,
4x^2+25+20 = x-2
Rearrange by moving the LHS to the RHS
4x^2-x+47=0
This is a standard form of quadratic equation
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