write 3/-4 in standard form
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Answer:
3/(4+i)]/[(4-i)/(4-i)]
= [3(4-i)]/[(4+i)(4-i)]
= (12 - 3i)/[4(4)+4(-i)+4i-i2]
= (12-3i)/(16-i2)
= (12-3i)/(16+1)
= (12-3i)/17
= 12/17 - (3/17)i
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