Question

Write 3 log 2-2 log 3 as a single logarithm

Answer 1

ACCORDING TO  mLOGX=LOGXm
log2³-log3²
log8-log9
log8/9(logx-logy=logx/y)

Answer 2

3log2-2log3
It is in the form of xlogy 
formulae for it is logy^x
3 log 2-2 log 3=log(2)^3-log(3)^2
                        =log(8)-log(9)
It is in the form of loga-logb
formulae for it is log(a/b)
log(8)-log(9)=log(8/9)